C++ アルゴリズムとデータ構造のライブラリ
#include "library/graph/shortest_path/warshall_froyd.hpp"dis: dis[i][j] := 頂点までの最小コストnegativeCycle: 負の閉路がある場合true$O(N^3)$
auto [dis, negativeCycle] = warshall_froyd(G);
#pragma once
#include "library/graph/base/graph.hpp"
pair<vector<vector<long long>>, bool> warshall_froyd(const Graph &G) {
int N = G.size();
vector<vector<long long>> dis(N, vector<long long>(N, INF));
for (int v = 0; v < N; ++v) {
dis[v][v] = 0;
for (auto &&[from, to, cost, idx] : G[v]) {
dis[v][to] = min(dis[v][to], cost);
}
}
for (int k = 0; k < N; ++k) {
for (int i = 0; i < N; ++i) {
if (dis[i][k] == INF) continue;
for (int j = 0; j < N; ++j) {
if (dis[k][j] == INF) continue;
dis[i][j] = min(dis[i][j], dis[i][k] + dis[k][j]);
}
}
}
bool negativeCycle = false;
for (int i = 0; i < N; ++i) {
if (dis[i][i] < 0) {
negativeCycle = true;
break;
}
}
return {dis, negativeCycle};
}#line 2 "library/graph/base/edge.hpp"
struct Edge {
int from, to;
long long cost;
int idx;
Edge(int from, int to, long long cost = 1, int idx = -1)
: from(from), to(to), cost(cost), idx(idx) {}
};
#line 3 "library/graph/base/graph.hpp"
struct Graph {
int N;
vector<vector<Edge>> G;
int es;
Graph() = default;
Graph(int N) : N(N), G(N), es(0) {}
const vector<Edge> &operator[](int v) const { return G[v]; }
int size() const { return N; }
void add(int from, int to, long long cost = 1) {
G[from].push_back(Edge(from, to, cost, es++));
}
void add_both(int from, int to, long long cost = 1) {
G[from].push_back(Edge(from, to, cost, es));
G[to].push_back(Edge(to, from, cost, es++));
}
void read(int M, int padding = -1, bool weighted = false,
bool directed = false) {
for (int i = 0; i < M; i++) {
int u, v;
cin >> u >> v;
u += padding, v += padding;
long long cost = 1ll;
if (weighted) cin >> cost;
if (directed) {
add(u, v, cost);
} else {
add_both(u, v, cost);
}
}
}
};
#line 3 "library/graph/shortest_path/warshall_froyd.hpp"
pair<vector<vector<long long>>, bool> warshall_froyd(const Graph &G) {
int N = G.size();
vector<vector<long long>> dis(N, vector<long long>(N, INF));
for (int v = 0; v < N; ++v) {
dis[v][v] = 0;
for (auto &&[from, to, cost, idx] : G[v]) {
dis[v][to] = min(dis[v][to], cost);
}
}
for (int k = 0; k < N; ++k) {
for (int i = 0; i < N; ++i) {
if (dis[i][k] == INF) continue;
for (int j = 0; j < N; ++j) {
if (dis[k][j] == INF) continue;
dis[i][j] = min(dis[i][j], dis[i][k] + dis[k][j]);
}
}
}
bool negativeCycle = false;
for (int i = 0; i < N; ++i) {
if (dis[i][i] < 0) {
negativeCycle = true;
break;
}
}
return {dis, negativeCycle};
}